Find the angle between two body diagonals in a unit cube. | Homework.Study.com
![Edge length of a cube is 400pm. Its body diagonal (in pm) would be:[A] 566[B] 600[C] 500[D] 693](https://www.vedantu.com/question-sets/4fe4a944-9f2c-437b-97ab-e350e21444618606447170386427521.png "Edge length of a cube is 400pm. Its body diagonal (in pm) would be:[A] 566[B] 600[C] 500[D] 693")
Edge length of a cube is 400pm. Its body diagonal (in pm) would be:[A] 566[B] 600[C] 500[D] 693
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netry: One plane (b) Diagonal planes of symmetry: One passing diagonally through the cube is shown in Fig. 6.22 can be a total of 6 such planes passing diagonally through the che
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![If 'a' the length of side of the cube, the distance between the body-centred atom and one corner atom in the cube will be:[A] $\\dfrac{4}{\\sqrt{3}}a$ [B] $\\dfrac{\\sqrt{3}}{4}a$ [C] $\\dfrac{\\sqrt{3}}{2}a$[D] $\\dfrac{2}{\\sqrt{3}}a$](https://www.vedantu.com/question-sets/720721fd-3ab5-4f3a-8864-68a0dfdd06901210945075913440462.png "If 'a' the length of side of the cube, the distance between the body-centred atom and one corner atom in the cube will be:[A] $\\dfrac{4}{\\sqrt{3}}a$ [B] $\\dfrac{\\sqrt{3}}{4}a$ [C] $\\dfrac{\\sqrt{3}}{2}a$[D] $\\dfrac{2}{\\sqrt{3}}a$")
If 'a' the length of side of the cube, the distance between the body-centred atom and one corner atom in the cube will be:[A] $\\dfrac{4}{\\sqrt{3}}a$ [B] $\\dfrac{\\sqrt{3}}{4}a$ [C] $\\dfrac{\\sqrt{3}}{2}a$[D] $\\dfrac{2}{\\sqrt{3}}a$
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there is a cubic frame on each corner a pont massm are kept tell about momet of inertia if axis is pass through body diagonal of cubeeach side of cube 1u06l1vv -Physics -
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